2(x+3)-2x=(x-4)+2

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Solution for 2(x+3)-2x=(x-4)+2 equation: 



2(x+3)-2x=(x-4)+2

We move all terms to the left:

2(x+3)-2x-((x-4)+2)=0

We add all the numbers together, and all the variables

-2x+2(x+3)-((x-4)+2)=0

We multiply parentheses

-2x+2x-((x-4)+2)+6=0



We calculate terms in parentheses: -((x-4)+2), so:

(x-4)+2

We get rid of parentheses

x-4+2

We add all the numbers together, and all the variables

x-2

Back to the equation:

-(x-2)



We add all the numbers together, and all the variables

-(x-2)+6=0

We get rid of parentheses

-x+2+6=0

We add all the numbers together, and all the variables

-1x+8=0

We move all terms containing x to the left, all other terms to the right

-x=-8

x=-8/-1

x=+8

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