3(z-6)=8(2z+1)

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Solution for 3(z-6)=8(2z+1) equation: 



3(z-6)=8(2z+1)

We move all terms to the left:

3(z-6)-(8(2z+1))=0

We multiply parentheses

3z-(8(2z+1))-18=0



We calculate terms in parentheses: -(8(2z+1)), so:

8(2z+1)

We multiply parentheses

16z+8

Back to the equation:

-(16z+8)



We get rid of parentheses

3z-16z-8-18=0

We add all the numbers together, and all the variables

-13z-26=0

We move all terms containing z to the left, all other terms to the right

-13z=26

z=26/-13

z=-2

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