(1)/(2)x-((1)/(2)x+4)+12=17x-6(3x+(5)/(6))

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Solution for (1)/(2)x-((1)/(2)x+4)+12=17x-6(3x+(5)/(6)) equation: 



(1)/(2)x-((1)/(2)x+4)+12=17x-6(3x+(5)/(6))

We move all terms to the left:

(1)/(2)x-((1)/(2)x+4)+12-(17x-6(3x+(5)/(6)))=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 2x+4)!=0

x∈R



We add all the numbers together, and all the variables

1/2x-(1/2x+4)-(17x-6(+3x+5/6))+12=0

We get rid of parentheses

1/2x-1/2x-(17x-6(+3x+5/6))-4+12=0

We calculate fractions


()/12x^2+(-(17x-6(+3x+5*2x)/12x^2-4+12=0

We calculate fractions

We do not support expression: x^4

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