2(x+2)=3(x+5)-3

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Solution for 2(x+2)=3(x+5)-3 equation: 



2(x+2)=3(x+5)-3

We move all terms to the left:

2(x+2)-(3(x+5)-3)=0

We multiply parentheses

2x-(3(x+5)-3)+4=0



We calculate terms in parentheses: -(3(x+5)-3), so:

3(x+5)-3

We multiply parentheses

3x+15-3

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

2x-3x-12+4=0

We add all the numbers together, and all the variables

-1x-8=0

We move all terms containing x to the left, all other terms to the right

-x=8

x=8/-1

x=-8

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