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6x^2+10x-2600=0
a = 6; b = 10; c = -2600;
Δ = b2-4ac
Δ = 102-4·6·(-2600)
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-250}{2*6}=\frac{-260}{12} =-21+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+250}{2*6}=\frac{240}{12} =20 $
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