112-(6x+16)=6(x+3)+x

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Solution for 112-(6x+16)=6(x+3)+x equation: 



112-(6x+16)=6(x+3)+x

We move all terms to the left:

112-(6x+16)-(6(x+3)+x)=0

We get rid of parentheses

-6x-(6(x+3)+x)-16+112=0



We calculate terms in parentheses: -(6(x+3)+x), so:

6(x+3)+x

We add all the numbers together, and all the variables

x+6(x+3)

We multiply parentheses

x+6x+18

We add all the numbers together, and all the variables

7x+18

Back to the equation:

-(7x+18)



We add all the numbers together, and all the variables

-6x-(7x+18)+96=0

We get rid of parentheses

-6x-7x-18+96=0

We add all the numbers together, and all the variables

-13x+78=0

We move all terms containing x to the left, all other terms to the right

-13x=-78

x=-78/-13

x=+6

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