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5(2y+3)=3(2y+9)
We move all terms to the left:
5(2y+3)-(3(2y+9))=0
We multiply parentheses
10y-(3(2y+9))+15=0
We calculate terms in parentheses: -(3(2y+9)), so:We get rid of parentheses
3(2y+9)
We multiply parentheses
6y+27
Back to the equation:
-(6y+27)
10y-6y-27+15=0
We add all the numbers together, and all the variables
4y-12=0
We move all terms containing y to the left, all other terms to the right
4y=12
y=12/4
y=3
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