2(h+1)+4(h+1)=12

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Solution for 2(h+1)+4(h+1)=12 equation: 



2(h+1)+4(h+1)=12

We move all terms to the left:

2(h+1)+4(h+1)-(12)=0

We multiply parentheses

2h+4h+2+4-12=0

We add all the numbers together, and all the variables

6h-6=0

We move all terms containing h to the left, all other terms to the right

6h=6

h=6/6

h=1

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