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-3x(x+11)-10x=6
We move all terms to the left:
-3x(x+11)-10x-(6)=0
We add all the numbers together, and all the variables
-10x-3x(x+11)-6=0
We multiply parentheses
-3x^2-10x-33x-6=0
We add all the numbers together, and all the variables
-3x^2-43x-6=0
a = -3; b = -43; c = -6;
Δ = b2-4ac
Δ = -432-4·(-3)·(-6)
Δ = 1777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-\sqrt{1777}}{2*-3}=\frac{43-\sqrt{1777}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+\sqrt{1777}}{2*-3}=\frac{43+\sqrt{1777}}{-6} $
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