20=3(2x-2)-2(5x-1)

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Solution for 20=3(2x-2)-2(5x-1) equation: 



20=3(2x-2)-2(5x-1)

We move all terms to the left:

20-(3(2x-2)-2(5x-1))=0



We calculate terms in parentheses: -(3(2x-2)-2(5x-1)), so:

3(2x-2)-2(5x-1)

We multiply parentheses

6x-10x-6+2

We add all the numbers together, and all the variables

-4x-4

Back to the equation:

-(-4x-4)



We get rid of parentheses

4x+4+20=0

We add all the numbers together, and all the variables

4x+24=0

We move all terms containing x to the left, all other terms to the right

4x=-24

x=-24/4

x=-6

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