2(y-4)=(y-4)+6

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Solution for 2(y-4)=(y-4)+6 equation: 



2(y-4)=(y-4)+6

We move all terms to the left:

2(y-4)-((y-4)+6)=0

We multiply parentheses

2y-((y-4)+6)-8=0



We calculate terms in parentheses: -((y-4)+6), so:

(y-4)+6

We get rid of parentheses

y-4+6

We add all the numbers together, and all the variables

y+2

Back to the equation:

-(y+2)



We get rid of parentheses

2y-y-2-8=0

We add all the numbers together, and all the variables

y-10=0

We move all terms containing y to the left, all other terms to the right

y=10

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