2(7-x)+6x=8-5(x-1)+8x+4

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Solution for 2(7-x)+6x=8-5(x-1)+8x+4 equation: 



2(7-x)+6x=8-5(x-1)+8x+4

We move all terms to the left:

2(7-x)+6x-(8-5(x-1)+8x+4)=0

We add all the numbers together, and all the variables

2(-1x+7)+6x-(8-5(x-1)+8x+4)=0

We add all the numbers together, and all the variables

6x+2(-1x+7)-(8-5(x-1)+8x+4)=0

We multiply parentheses

6x-2x-(8-5(x-1)+8x+4)+14=0



We calculate terms in parentheses: -(8-5(x-1)+8x+4), so:

8-5(x-1)+8x+4

determiningTheFunctionDomain
-5(x-1)+8x+8+4

We add all the numbers together, and all the variables

8x-5(x-1)+12

We multiply parentheses

8x-5x+5+12

We add all the numbers together, and all the variables

3x+17

Back to the equation:

-(3x+17)



We add all the numbers together, and all the variables

4x-(3x+17)+14=0

We get rid of parentheses

4x-3x-17+14=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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