4x-2(1-3x)=5-3(x+2)

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Solution for 4x-2(1-3x)=5-3(x+2) equation: 



4x-2(1-3x)=5-3(x+2)

We move all terms to the left:

4x-2(1-3x)-(5-3(x+2))=0

We add all the numbers together, and all the variables

4x-2(-3x+1)-(5-3(x+2))=0

We multiply parentheses

4x+6x-(5-3(x+2))-2=0



We calculate terms in parentheses: -(5-3(x+2)), so:

5-3(x+2)

determiningTheFunctionDomain
-3(x+2)+5

We multiply parentheses

-3x-6+5

We add all the numbers together, and all the variables

-3x-1

Back to the equation:

-(-3x-1)



We add all the numbers together, and all the variables

10x-(-3x-1)-2=0

We get rid of parentheses

10x+3x+1-2=0

We add all the numbers together, and all the variables

13x-1=0

We move all terms containing x to the left, all other terms to the right

13x=1

x=1/13

x=1/13

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