y-(8/y)=-7

Solution for y-(8/y)=-7 equation:

y-(8/y)=-7

We move all terms to the left:

y-(8/y)-(-7)=0


Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

y-(+8/y)-(-7)=0

We add all the numbers together, and all the variables

y-(+8/y)+7=0

We get rid of parentheses

y-8/y+7=0

We multiply all the terms by the denominator


y*y+7*y-8=0

We add all the numbers together, and all the variables

7y+y*y-8=0

Wy multiply elements

y^2+7y-8=0

a = 1; b = 7; c = -8;
Δ = b2-4ac
Δ = 72-4·1·(-8)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-9}{2*1}=\frac{-16}{2}
=-8
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+9}{2*1}=\frac{2}{2}
=1
$