.2(5z-5)=4(4z+1)

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Solution for .2(5z-5)=4(4z+1) equation: 



.2(5z-5)=4(4z+1)

We move all terms to the left:

.2(5z-5)-(4(4z+1))=0

We multiply parentheses

z-(4(4z+1))-1=0



We calculate terms in parentheses: -(4(4z+1)), so:

4(4z+1)

We multiply parentheses

16z+4

Back to the equation:

-(16z+4)



We get rid of parentheses

z-16z-4-1=0

We add all the numbers together, and all the variables

-15z-5=0

We move all terms containing z to the left, all other terms to the right

-15z=5

z=5/-15

z=-1/3

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