2(5x-3)+7x-4=3(2x-4)+11x

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Solution for 2(5x-3)+7x-4=3(2x-4)+11x equation: 



2(5x-3)+7x-4=3(2x-4)+11x

We move all terms to the left:

2(5x-3)+7x-4-(3(2x-4)+11x)=0

We add all the numbers together, and all the variables

7x+2(5x-3)-(3(2x-4)+11x)-4=0

We multiply parentheses

7x+10x-(3(2x-4)+11x)-6-4=0



We calculate terms in parentheses: -(3(2x-4)+11x), so:

3(2x-4)+11x

We add all the numbers together, and all the variables

11x+3(2x-4)

We multiply parentheses

11x+6x-12

We add all the numbers together, and all the variables

17x-12

Back to the equation:

-(17x-12)



We add all the numbers together, and all the variables

17x-(17x-12)-10=0

We get rid of parentheses

17x-17x+12-10=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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