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3(3x+4)=2x-(4+x)
We move all terms to the left:
3(3x+4)-(2x-(4+x))=0
We add all the numbers together, and all the variables
3(3x+4)-(2x-(x+4))=0
We multiply parentheses
9x-(2x-(x+4))+12=0
We calculate terms in parentheses: -(2x-(x+4)), so:We get rid of parentheses
2x-(x+4)
We get rid of parentheses
2x-x-4
We add all the numbers together, and all the variables
x-4
Back to the equation:
-(x-4)
9x-x+4+12=0
We add all the numbers together, and all the variables
8x+16=0
We move all terms containing x to the left, all other terms to the right
8x=-16
x=-16/8
x=-2
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