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x*x+15x-95=0
We add all the numbers together, and all the variables
15x+x*x-95=0
Wy multiply elements
x^2+15x-95=0
a = 1; b = 15; c = -95;
Δ = b2-4ac
Δ = 152-4·1·(-95)
Δ = 605
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{605}=\sqrt{121*5}=\sqrt{121}*\sqrt{5}=11\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-11\sqrt{5}}{2*1}=\frac{-15-11\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+11\sqrt{5}}{2*1}=\frac{-15+11\sqrt{5}}{2} $
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