2(4n-3)=10(n-1)

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Solution for 2(4n-3)=10(n-1) equation: 



2(4n-3)=10(n-1)

We move all terms to the left:

2(4n-3)-(10(n-1))=0

We multiply parentheses

8n-(10(n-1))-6=0



We calculate terms in parentheses: -(10(n-1)), so:

10(n-1)

We multiply parentheses

10n-10

Back to the equation:

-(10n-10)



We get rid of parentheses

8n-10n+10-6=0

We add all the numbers together, and all the variables

-2n+4=0

We move all terms containing n to the left, all other terms to the right

-2n=-4

n=-4/-2

n=+2

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