2(3y-6)=4(y-5)+4

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Solution for 2(3y-6)=4(y-5)+4 equation: 



2(3y-6)=4(y-5)+4

We move all terms to the left:

2(3y-6)-(4(y-5)+4)=0

We multiply parentheses

6y-(4(y-5)+4)-12=0



We calculate terms in parentheses: -(4(y-5)+4), so:

4(y-5)+4

We multiply parentheses

4y-20+4

We add all the numbers together, and all the variables

4y-16

Back to the equation:

-(4y-16)



We get rid of parentheses

6y-4y+16-12=0

We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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