2(3x-5)-4x=7(x+1)+3

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Solution for 2(3x-5)-4x=7(x+1)+3 equation: 



2(3x-5)-4x=7(x+1)+3

We move all terms to the left:

2(3x-5)-4x-(7(x+1)+3)=0

We add all the numbers together, and all the variables

-4x+2(3x-5)-(7(x+1)+3)=0

We multiply parentheses

-4x+6x-(7(x+1)+3)-10=0



We calculate terms in parentheses: -(7(x+1)+3), so:

7(x+1)+3

We multiply parentheses

7x+7+3

We add all the numbers together, and all the variables

7x+10

Back to the equation:

-(7x+10)



We add all the numbers together, and all the variables

2x-(7x+10)-10=0

We get rid of parentheses

2x-7x-10-10=0

We add all the numbers together, and all the variables

-5x-20=0

We move all terms containing x to the left, all other terms to the right

-5x=20

x=20/-5

x=-4

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