8x+4=10x2+5x

Solution for 8x+4=10x2+5x equation:

8x+4=10x^2+5x

We move all terms to the left:

8x+4-(10x^2+5x)=0

We get rid of parentheses

-10x^2+8x-5x+4=0

We add all the numbers together, and all the variables

-10x^2+3x+4=0

a = -10; b = 3; c = +4;
Δ = b2-4ac
Δ = 32-4·(-10)·4
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-13}{2*-10}=\frac{-16}{-20}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+13}{2*-10}=\frac{10}{-20}
=-1/2
$