2(3x-4)=(4x+3)=8(2X+1

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Solution for 2(3x-4)=(4x+3)=8(2X+1 equation: 



2(3x-4)=(4x+3)=8(2x+1

We move all terms to the left:

2(3x-4)-((4x+3))=0

We multiply parentheses

6x-((4x+3))-8=0



We calculate terms in parentheses: -((4x+3)), so:

(4x+3)

We get rid of parentheses

4x+3

Back to the equation:

-(4x+3)



We get rid of parentheses

6x-4x-3-8=0

We add all the numbers together, and all the variables

2x-11=0

We move all terms containing x to the left, all other terms to the right

2x=11

x=11/2

x=5+1/2

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