n+3(n+2)=n-10+3(n+2)

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Solution for n+3(n+2)=n-10+3(n+2) equation: 



n+3(n+2)=n-10+3(n+2)

We move all terms to the left:

n+3(n+2)-(n-10+3(n+2))=0

We multiply parentheses

n+3n-(n-10+3(n+2))+6=0



We calculate terms in parentheses: -(n-10+3(n+2)), so:

n-10+3(n+2)

determiningTheFunctionDomain
n+3(n+2)-10

We multiply parentheses

n+3n+6-10

We add all the numbers together, and all the variables

4n-4

Back to the equation:

-(4n-4)



We add all the numbers together, and all the variables

4n-(4n-4)+6=0

We get rid of parentheses

4n-4n+4+6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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