6(x+1)+2=3(2/5x+1)+3

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Solution for 6(x+1)+2=3(2/5x+1)+3 equation: 



6(x+1)+2=3(2/5x+1)+3

We move all terms to the left:

6(x+1)+2-(3(2/5x+1)+3)=0



Domain of the equation: 5x+1)+3)!=0

x∈R



We multiply parentheses

6x-(3(2/5x+1)+3)+6+2=0

We multiply all the terms by the denominator


6x*5x+6*5x+1)+3)+2*5x+1)+3)+1)+3)-(3(2=0

Wy multiply elements

30x^2+30x+1)+3)+2*5x+1)+3)+1)+3)-(3(2=0

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