2600=(2x-6)+(x+3)

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Solution for 2600=(2x-6)+(x+3) equation: 



2600=(2x-6)+(x+3)

We move all terms to the left:

2600-((2x-6)+(x+3))=0



We calculate terms in parentheses: -((2x-6)+(x+3)), so:

(2x-6)+(x+3)

We get rid of parentheses

2x+x-6+3

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We get rid of parentheses

-3x+3+2600=0

We add all the numbers together, and all the variables

-3x+2603=0

We move all terms containing x to the left, all other terms to the right

-3x=-2603

x=-2603/-3

x=867+2/3

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