4x+5(4x-3)=9(x-5)

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Solution for 4x+5(4x-3)=9(x-5) equation: 



4x+5(4x-3)=9(x-5)

We move all terms to the left:

4x+5(4x-3)-(9(x-5))=0

We multiply parentheses

4x+20x-(9(x-5))-15=0



We calculate terms in parentheses: -(9(x-5)), so:

9(x-5)

We multiply parentheses

9x-45

Back to the equation:

-(9x-45)



We add all the numbers together, and all the variables

24x-(9x-45)-15=0

We get rid of parentheses

24x-9x+45-15=0

We add all the numbers together, and all the variables

15x+30=0

We move all terms containing x to the left, all other terms to the right

15x=-30

x=-30/15

x=-2

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