(4/5)m+2=6

Solution for (4/5)m+2=6 equation:

(4/5)m+2=6

We move all terms to the left:

(4/5)m+2-(6)=0


Domain of the equation: 5)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+4/5)m+2-6=0

We add all the numbers together, and all the variables

(+4/5)m-4=0

We multiply parentheses

4m^2-4=0

a = 4; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·4·(-4)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*4}=\frac{-8}{8}
=-1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*4}=\frac{8}{8}
=1
$