2(b-5)+14=6b-3(b+8)

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Solution for 2(b-5)+14=6b-3(b+8) equation: 



2(b-5)+14=6b-3(b+8)

We move all terms to the left:

2(b-5)+14-(6b-3(b+8))=0

We multiply parentheses

2b-(6b-3(b+8))-10+14=0



We calculate terms in parentheses: -(6b-3(b+8)), so:

6b-3(b+8)

We multiply parentheses

6b-3b-24

We add all the numbers together, and all the variables

3b-24

Back to the equation:

-(3b-24)



We add all the numbers together, and all the variables

2b-(3b-24)+4=0

We get rid of parentheses

2b-3b+24+4=0

We add all the numbers together, and all the variables

-1b+28=0

We move all terms containing b to the left, all other terms to the right

-b=-28

b=-28/-1

b=+28

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