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6(x+1)+2=3(5/5x+1)+3
We move all terms to the left:
6(x+1)+2-(3(5/5x+1)+3)=0
Domain of the equation: 5x+1)+3)!=0We multiply parentheses
x∈R
6x-(3(5/5x+1)+3)+6+2=0
We multiply all the terms by the denominator
6x*5x+6*5x+1)+3)+2*5x+1)+3)+1)+3)-(3(5=0
Wy multiply elements
30x^2+30x+1)+3)+2*5x+1)+3)+1)+3)-(3(5=0
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