2(3c-5)+9=19

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Solution for 2(3c-5)+9=19 equation: 



2(3c-5)+9=19

We move all terms to the left:

2(3c-5)+9-(19)=0

We add all the numbers together, and all the variables

2(3c-5)-10=0

We multiply parentheses

6c-10-10=0

We add all the numbers together, and all the variables

6c-20=0

We move all terms containing c to the left, all other terms to the right

6c=20

c=20/6

c=3+1/3

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