2(x-5)=-3(2x-2)

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Solution for 2(x-5)=-3(2x-2) equation: 



2(x-5)=-3(2x-2)

We move all terms to the left:

2(x-5)-(-3(2x-2))=0

We multiply parentheses

2x-(-3(2x-2))-10=0



We calculate terms in parentheses: -(-3(2x-2)), so:

-3(2x-2)

We multiply parentheses

-6x+6

Back to the equation:

-(-6x+6)



We get rid of parentheses

2x+6x-6-10=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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