5+3(y-4)=5(y+2-y

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Solution for 5+3(y-4)=5(y+2-y equation:



5+3(y-4)=5(y+2-y
We move all terms to the left:
5+3(y-4)-(5(y+2-y)=0
We add all the numbers together, and all the variables
3(y-4)-(52+5=0
We add all the numbers together, and all the variables
3(y-4)=0
We multiply parentheses
3y-12=0
We move all terms containing y to the left, all other terms to the right
3y=12
y=12/3
y=4

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