6+3(2y-2)=-3(6y-2)+8y

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Solution for 6+3(2y-2)=-3(6y-2)+8y equation: 



6+3(2y-2)=-3(6y-2)+8y

We move all terms to the left:

6+3(2y-2)-(-3(6y-2)+8y)=0

We multiply parentheses

6y-(-3(6y-2)+8y)-6+6=0



We calculate terms in parentheses: -(-3(6y-2)+8y), so:

-3(6y-2)+8y

We add all the numbers together, and all the variables

8y-3(6y-2)

We multiply parentheses

8y-18y+6

We add all the numbers together, and all the variables

-10y+6

Back to the equation:

-(-10y+6)



We add all the numbers together, and all the variables

6y-(-10y+6)=0

We get rid of parentheses

6y+10y-6=0

We add all the numbers together, and all the variables

16y-6=0

We move all terms containing y to the left, all other terms to the right

16y=6

y=6/16

y=3/8

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