2(2k-2)-4=2(k+1)

Solution for 2(2k-2)-4=2(k+1) equation:

2(2k-2)-4=2(k+1)

We move all terms to the left:

2(2k-2)-4-(2(k+1))=0

We multiply parentheses

4k-(2(k+1))-4-4=0


We calculate terms in parentheses: -(2(k+1)), so:

2(k+1)

We multiply parentheses

2k+2

Back to the equation:

-(2k+2)


We add all the numbers together, and all the variables

4k-(2k+2)-8=0

We get rid of parentheses

4k-2k-2-8=0

We add all the numbers together, and all the variables

2k-10=0

We move all terms containing k to the left, all other terms to the right

2k=10

k=10/2

k=5