4(3n-2)-5(5n+2)=3n-98

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Solution for 4(3n-2)-5(5n+2)=3n-98 equation: 



4(3n-2)-5(5n+2)=3n-98

We move all terms to the left:

4(3n-2)-5(5n+2)-(3n-98)=0

We multiply parentheses

12n-25n-(3n-98)-8-10=0

We get rid of parentheses

12n-25n-3n+98-8-10=0

We add all the numbers together, and all the variables

-16n+80=0

We move all terms containing n to the left, all other terms to the right

-16n=-80

n=-80/-16

n=+5

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