z-8=3(2-z)-2

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Solution for z-8=3(2-z)-2 equation: 



z-8=3(2-z)-2

We move all terms to the left:

z-8-(3(2-z)-2)=0

We add all the numbers together, and all the variables

z-(3(-1z+2)-2)-8=0



We calculate terms in parentheses: -(3(-1z+2)-2), so:

3(-1z+2)-2

We multiply parentheses

-3z+6-2

We add all the numbers together, and all the variables

-3z+4

Back to the equation:

-(-3z+4)



We get rid of parentheses

z+3z-4-8=0

We add all the numbers together, and all the variables

4z-12=0

We move all terms containing z to the left, all other terms to the right

4z=12

z=12/4

z=3

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