11(p-4)+5=3(p+5)+18

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Solution for 11(p-4)+5=3(p+5)+18 equation: 



11(p-4)+5=3(p+5)+18

We move all terms to the left:

11(p-4)+5-(3(p+5)+18)=0

We multiply parentheses

11p-(3(p+5)+18)-44+5=0



We calculate terms in parentheses: -(3(p+5)+18), so:

3(p+5)+18

We multiply parentheses

3p+15+18

We add all the numbers together, and all the variables

3p+33

Back to the equation:

-(3p+33)



We add all the numbers together, and all the variables

11p-(3p+33)-39=0

We get rid of parentheses

11p-3p-33-39=0

We add all the numbers together, and all the variables

8p-72=0

We move all terms containing p to the left, all other terms to the right

8p=72

p=72/8

p=9

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