17y2=34y

Solution for 17y2=34y equation:

17y^2=34y

We move all terms to the left:

17y^2-(34y)=0

a = 17; b = -34; c = 0;
Δ = b2-4ac
Δ = -342-4·17·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-34}{2*17}=\frac{0}{34}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+34}{2*17}=\frac{68}{34}
=2
$