(2x-5)+5x+2x+2x+(6x-5)+(3x+10)=360

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Solution for (2x-5)+5x+2x+2x+(6x-5)+(3x+10)=360 equation: 



(2x-5)+5x+2x+2x+(6x-5)+(3x+10)=360

We move all terms to the left:

(2x-5)+5x+2x+2x+(6x-5)+(3x+10)-(360)=0

We add all the numbers together, and all the variables

9x+(2x-5)+(6x-5)+(3x+10)-360=0

We get rid of parentheses

9x+2x+6x+3x-5-5+10-360=0

We add all the numbers together, and all the variables

20x-360=0

We move all terms containing x to the left, all other terms to the right

20x=360

x=360/20

x=18

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