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5+1/4x=5/8x+2
We move all terms to the left:
5+1/4x-(5/8x+2)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 8x+2)!=0We get rid of parentheses
x∈R
1/4x-5/8x-2+5=0
We calculate fractions
8x/32x^2+(-20x)/32x^2-2+5=0
We add all the numbers together, and all the variables
8x/32x^2+(-20x)/32x^2+3=0
We multiply all the terms by the denominator
8x+(-20x)+3*32x^2=0
Wy multiply elements
96x^2+8x+(-20x)=0
We get rid of parentheses
96x^2+8x-20x=0
We add all the numbers together, and all the variables
96x^2-12x=0
a = 96; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·96·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*96}=\frac{0}{192} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*96}=\frac{24}{192} =1/8 $
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