3(2x+4)+8=503(2x+4)+8=50

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Solution for 3(2x+4)+8=503(2x+4)+8=50 equation: 



3(2x+4)+8=503(2x+4)+8=50

We move all terms to the left:

3(2x+4)+8-(503(2x+4)+8)=0

We multiply parentheses

6x-(503(2x+4)+8)+12+8=0



We calculate terms in parentheses: -(503(2x+4)+8), so:

503(2x+4)+8

We multiply parentheses

1006x+2012+8

We add all the numbers together, and all the variables

1006x+2020

Back to the equation:

-(1006x+2020)



We add all the numbers together, and all the variables

6x-(1006x+2020)+20=0

We get rid of parentheses

6x-1006x-2020+20=0

We add all the numbers together, and all the variables

-1000x-2000=0

We move all terms containing x to the left, all other terms to the right

-1000x=2000

x=2000/-1000

x=-2

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