15=-3(c-2)

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Solution for 15=-3(c-2) equation: 



15=-3(c-2)

We move all terms to the left:

15-(-3(c-2))=0



We calculate terms in parentheses: -(-3(c-2)), so:

-3(c-2)

We multiply parentheses

-3c+6

Back to the equation:

-(-3c+6)



We get rid of parentheses

3c-6+15=0

We add all the numbers together, and all the variables

3c+9=0

We move all terms containing c to the left, all other terms to the right

3c=-9

c=-9/3

c=-3

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