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x+(x+1)+(x+2)=(2x-6)+(2x+2)
We move all terms to the left:
x+(x+1)+(x+2)-((2x-6)+(2x+2))=0
We get rid of parentheses
x+x+x-((2x-6)+(2x+2))+1+2=0
We calculate terms in parentheses: -((2x-6)+(2x+2)), so:We add all the numbers together, and all the variables
(2x-6)+(2x+2)
We get rid of parentheses
2x+2x-6+2
We add all the numbers together, and all the variables
4x-4
Back to the equation:
-(4x-4)
3x-(4x-4)+3=0
We get rid of parentheses
3x-4x+4+3=0
We add all the numbers together, and all the variables
-1x+7=0
We move all terms containing x to the left, all other terms to the right
-x=-7
x=-7/-1
x=+7
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