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2(x+5)+2=6x-4(-4+x)
We move all terms to the left:
2(x+5)+2-(6x-4(-4+x))=0
We add all the numbers together, and all the variables
2(x+5)-(6x-4(x-4))+2=0
We multiply parentheses
2x-(6x-4(x-4))+10+2=0
We calculate terms in parentheses: -(6x-4(x-4)), so:We add all the numbers together, and all the variables
6x-4(x-4)
We multiply parentheses
6x-4x+16
We add all the numbers together, and all the variables
2x+16
Back to the equation:
-(2x+16)
2x-(2x+16)+12=0
We get rid of parentheses
2x-2x-16+12=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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