4(3x-2)=8(2x-2)

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Solution for 4(3x-2)=8(2x-2) equation: 



4(3x-2)=8(2x-2)

We move all terms to the left:

4(3x-2)-(8(2x-2))=0

We multiply parentheses

12x-(8(2x-2))-8=0



We calculate terms in parentheses: -(8(2x-2)), so:

8(2x-2)

We multiply parentheses

16x-16

Back to the equation:

-(16x-16)



We get rid of parentheses

12x-16x+16-8=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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