15=(3/4)(9x+8)

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Solution for 15=(3/4)(9x+8) equation: 



15=(3/4)(9x+8)

We move all terms to the left:

15-((3/4)(9x+8))=0



Domain of the equation: 4)(9x+8))!=0

x∈R



We add all the numbers together, and all the variables

-((+3/4)(9x+8))+15=0

We multiply parentheses ..

-((+27x^2+3/4*8))+15=0

We multiply all the terms by the denominator


-((+27x^2+3+15*4*8))=0



We calculate terms in parentheses: -((+27x^2+3+15*4*8)), so:

(+27x^2+3+15*4*8)

We get rid of parentheses

27x^2+3+15*4*8

We add all the numbers together, and all the variables

27x^2+483

Back to the equation:

-(27x^2+483)



We get rid of parentheses

-27x^2-483=0

a = -27; b = 0; c = -483;
Δ = b2-4ac
Δ = 02-4·(-27)·(-483)
Δ = -52164
Delta is less than zero, so there is no solution for the equation

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