-5/4p+1/3p=11/6

Solution for -5/4p+1/3p=11/6 equation:

-5/4p+1/3p=11/6

We move all terms to the left:

-5/4p+1/3p-(11/6)=0


Domain of the equation: 4p!=0

p!=0/4

p!=0

p∈R



Domain of the equation: 3p!=0

p!=0/3

p!=0

p∈R


We add all the numbers together, and all the variables

-5/4p+1/3p-(+11/6)=0

We get rid of parentheses

-5/4p+1/3p-11/6=0

We calculate fractions


(-396p^2)/432p^2+(-540p)/432p^2+144p/432p^2=0

We multiply all the terms by the denominator


(-396p^2)+(-540p)+144p=0

We add all the numbers together, and all the variables

(-396p^2)+144p+(-540p)=0

We get rid of parentheses

-396p^2+144p-540p=0

We add all the numbers together, and all the variables

-396p^2-396p=0

a = -396; b = -396; c = 0;
Δ = b2-4ac
Δ = -3962-4·(-396)·0
Δ = 156816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{156816}=396$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-396)-396}{2*-396}=\frac{0}{-792}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-396)+396}{2*-396}=\frac{792}{-792}
=-1
$