4/x+3=7/2x+10

Solution for 4/x+3=7/2x+10 equation:

4/x+3=7/2x+10

We move all terms to the left:

4/x+3-(7/2x+10)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x+10)!=0

x∈R


We get rid of parentheses

4/x-7/2x-10+3=0

We calculate fractions


8x/2x^2+(-7x)/2x^2-10+3=0

We add all the numbers together, and all the variables

8x/2x^2+(-7x)/2x^2-7=0

We multiply all the terms by the denominator


8x+(-7x)-7*2x^2=0

Wy multiply elements

-14x^2+8x+(-7x)=0

We get rid of parentheses

-14x^2+8x-7x=0

We add all the numbers together, and all the variables

-14x^2+x=0

a = -14; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-14)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-14}=\frac{-2}{-28}
=1/14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-14}=\frac{0}{-28}
=0
$