(x+1)+(x-2)=(4x-15)

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Solution for (x+1)+(x-2)=(4x-15) equation: 



(x+1)+(x-2)=(4x-15)

We move all terms to the left:

(x+1)+(x-2)-((4x-15))=0

We get rid of parentheses

x+x-((4x-15))+1-2=0



We calculate terms in parentheses: -((4x-15)), so:

(4x-15)

We get rid of parentheses

4x-15

Back to the equation:

-(4x-15)



We add all the numbers together, and all the variables

2x-(4x-15)-1=0

We get rid of parentheses

2x-4x+15-1=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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